Question

for problems 5–8, round to the underlined digit. (note: “≈” means “approximately”)

1. \underline{2}7.38 ≈ \square
2. 2.\underline{9}9 ≈ \square
3. 3.1\underline{6}7 ≈ \square
4. 1,00\underline{1}.45 ≈ \square

for problems 9–10, use a = 10 and b = 2.

1. the product of a and b is \square.
2. three more than twice b is \square.

Explanation:

Problem 5:

Step1: Identify the underlined digit (tens place, 2)

We look at the next digit (7) to round. Since \(7 \geq 5\), we round up the tens place.

Step2: Round 27.38 to the tens place

\(27.38 \approx 30\) (because we round the 2 in the tens place up to 3, and set the ones and decimal places to 0)

Problem 6:

Step1: Identify the underlined digit (ones place, 2)

Look at the next digit (9) to round. Since \(9 \geq 5\), we round up the ones place.

Step2: Round 2.99 to the ones place

\(2.99 \approx 3\) (rounding the 2 up to 3 as the next digit 9 is ≥5)

Problem 7:

Step1: Identify the underlined digit (tenths place, 1)

Look at the next digit (6) to round. Since \(6 \geq 5\), we round up the tenths place.

Step2: Round 3.167 to the tenths place

\(3.167 \approx 3.2\) (rounding the 1 in tenths place up to 2 as the next digit 6 is ≥5)

Problem 8:

Answer:

s:
Problem 5: \(30\)
Problem 6: \(3\)
Problem 7: \(3.2\)
Problem 8: \(1.001\)
Problem 9: \(20\)
Problem 10: \(7\)