Question

question 2 (multiple - choice worth 2 points) conditional probability lc the probability of event a occurring is 0.32, the probability of event b occurring is 0.11, and the probability of events a and b occurring is 0.02. determine p(b|a). 0.035 0.063 0.182 0.430

Explanation:

Step1: Recall conditional - probability formula

The formula for conditional probability is $P(B|A)=\frac{P(A\cap B)}{P(A)}$.

Step2: Substitute given values

We are given that $P(A) = 0.32$, $P(A\cap B)=0.02$. Substituting these values into the formula, we get $P(B|A)=\frac{0.02}{0.32}$.

Step3: Calculate the result

$\frac{0.02}{0.32}=\frac{2}{32}=\frac{1}{16}=0.0625\approx0.063$.

Answer:

0.063