Question

question 5
e and f are mutually exclusive events. p(e) = 0.91; p(f) = 0.42. find p(e | f)

Explanation:

Step1: Recall the definition of mutually - exclusive events

If E and F are mutually exclusive events, then \(P(E\cap F)=0\).

Step2: Recall the formula for conditional probability

The formula for conditional probability is \(P(E|F)=\frac{P(E\cap F)}{P(F)}\).

Step3: Substitute the value of \(P(E\cap F)\) into the conditional - probability formula

Since \(P(E\cap F) = 0\) (because E and F are mutually exclusive) and \(P(F)=0.42\), then \(P(E|F)=\frac{0}{0.42}=0\).

Answer:

0