Question

question 3
1 pts
given the probability distribution below, find ( p(x > 5) ).

( x )	( p(x) )
2	.18
5	.12
7	.19
8	.20

\\( \circ \\) 0.39
\\( \circ \\) 0.51
\\( \circ \\) 0.49
\\( \circ \\) 0.61
\\( \circ \\) 0.12
question 4
1 pts
( p(x) = \frac{x}{28} ) is a probability distribution function for values of ( x ): 1, 2, 3, 4, 5, 6, 7. find ( p(x = 14) )
\\( \circ \\) none of these
\\( \circ \\) 0
\\( \circ \\).75
\\( \circ \\).25
\\( \circ \\).5
question 5
1 pts

Explanation:

Question 3

Step1: Identify x > 5

Find x values greater than 5: 7, 8.

Step2: Sum their probabilities

\( P(X > 5) = p(7) + p(8) = 0.19 + 0.20 \)

Step3: Calculate the sum

\( 0.19 + 0.20 = 0.39 \)

Step1: Check X values

The possible X values are 1, 2, 3, 4, 5, 6, 7. 14 is not in this set.

Step2: Determine probability

For a probability distribution, \( P(X = 14) = 0 \) (since 14 is not a possible value).

Answer:

0.39

Question 4