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question 4
suppose p varies directly with q and that p = 72 when q = 9. what is the value of p when q = 6?
p =
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Step1: Define direct variation
$p = kq$, where $k$ is constant.
Step2: Solve for $k$
Substitute $p=72, q=9$:
$72 = 9k$
$k = \frac{72}{9} = 8$
Step3: Find $p$ when $q=6$
Use $k=8, q=6$:
$p = 8 \times 6$
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