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question when deepa left her house this morning, her cell phone was 60%…

Question

question when deepa left her house this morning, her cell phone was 60% charged and it then started to lose 5% charge for each hour thereafter. write an equation for b, in terms of t, representing the charge remaining in deepas battery, as a percentage, t hours after deepa left her house.

Explanation:

Step1: Identify initial and rate values

Initial charge is 60% and rate of loss is 5% per hour.

Step2: Write linear - equation formula

The general form of a linear equation is $y = mx + b$, where $m$ is the slope and $b$ is the y - intercept. Here, $B$ (charge remaining) is $y$, $t$ (hours) is $x$, the rate of loss of 5% is $m=- 5$ (negative because it's a loss), and the initial charge of 60% is $b = 60$.
So the equation is $B=60 - 5t$.

Answer:

$B = 60-5t$