Question

questions on contingency tables
the following five questions refer to the table below showing beer preferences in a random sample of male and female beer drinkers

	male	female
regular beer	57	20
dark beer	25	8

question 16 (1 point)
for a visual representation of the data, we should construct:

• side by side pie-charts
• side by side box and whisker plots
• side by side scatterplots
• side by side bar charts

question 17 (1 point)
this is a:

• q to c problem
• c to q problem
• q to q problem
• c to c problem

question 18 (1 point)
among beer drinkers:

• 33.5% are males and 66.5% are females
• 55% are males and 45% are females
• 66.5% are males and 33.5% are females
• 45% are males and 55% are females

question 19 (1 point)
among light beer drinkers:

• 57% are females
• 26% are females
• 26% are males
• 43% are females

question 20 (1 point)
among males:

• 58% drink light beer
• 30% drink regular beer
• 43% drink regular beer
• 12% drink dark beer

Explanation:

Question 16

The data is about beer preferences (categories: Light, Regular, Dark) for two groups (Male, Female). Side - by - side bar charts are suitable for comparing categorical data across different groups. Pie charts are good for showing proportions within a single group, box - and - whisker plots for numerical data distribution, and scatterplots for relationships between two numerical variables. So side - by - side bar charts are the right choice.

The variables here are gender (categorical: Male, Female) and beer type (categorical: Light, Regular, Dark). A C to C (categorical to categorical) problem involves analyzing the relationship between two categorical variables, which is the case here.

First, calculate the total number of beer drinkers. For males: \(51 + 57+25=133\). For females: \(39 + 20 + 8 = 67\). Total \(=133 + 67=200\). Percentage of males: \(\frac{133}{200}\times100 = 66.5\%\), percentage of females: \(\frac{67}{200}\times100=33.5\%\).

Answer:

D. Side by side bar charts

Question 17