Question

remember, the female on the left should have white fur and the male should have black fur. their offspring should have a 50:50 split between black and white fur. hint: start by figuring out the females genotype. then adjust the males genotype until you get a 50:50 split in fur color among the offspring. genotype of the female: bb bb bb offspring percentages: 100% 0%

Explanation:

Step1: Understand dominant - recessive traits

Assume black fur (B) is dominant over white fur (b). The female has white fur, so her genotype must be homozygous recessive (bb) since the recessive trait is only expressed in the homozygous state.

Step2: Set up Punnett - square with male

Let the male's genotype be Bb. When we set up a Punnett - square with female (bb) and male (Bb), we have:

	B	b
b	Bb	bb

The resulting genotypes of the offspring are Bb (black - furred) and bb (white - furred) in a 1:1 ratio or 50:50 split.

Answer:

Genotype of the Female: bb