Question

reyesburg corporation is contemplating using a new glue in the construction of its laminated veneer lumber. of importance to the company is the carrying load of the lumber. the company has tested 25 beams using the new glue, recording for each beam the pressure (in pounds per square foot) at which the beam broke. the data collected are presented in the following histogram. based on the histogram, draw the ogive (the cumulative frequency polygon) for the reyesburg data.

Explanation:

Step1: Calculate cumulative frequencies

• For 860: Cumulative frequency (CF) = 4 (since first bar has frequency 4)
• For 880: CF = 4 + 5 = 9 (sum of first two bars' frequencies)
• For 900: CF = 9 + 9 = 18 (sum of first three bars' frequencies)
• For 920: CF = 18 + 4 = 22 (sum of first four bars' frequencies)
• For 940: CF = 22 + 3 = 25 (sum of all bars' frequencies)
• For 960: CF remains 25 (no more data)

Step2: Plot points

• Plot (860, 4), (880, 9), (900, 18), (920, 22), (940, 25), (960, 25) on the cumulative frequency vs. carrying load graph.

Step3: Draw the ogive

• Connect the plotted points with straight lines to form the cumulative frequency polygon (ogive).

Answer:

The ogive is drawn by plotting cumulative frequencies (4, 9, 18, 22, 25, 25) at carrying loads 860, 880, 900, 920, 940, 960 respectively and connecting them.