Question

rivera algebra 1 unit 2 practice problem a wildlife train is observing the feeding behavior of two species. the table shows the results. | | eats at night | eats during day | |---|---|---| | owls | 18 | 6 | | hawks | 6 | 20 | according to the table, what percentage of the observed animals are more likely to eat at night? | 36% | 40% | 44% | 52% |

Explanation:

Step1: Calculate total night eaters

$18 + 6 = 24$

Step2: Calculate total observed animals

$18 + 6 + 6 + 20 = 50$

Step3: Compute percentage

$\frac{24}{50} \times 100\% = 48\%$

Answer:

C. 48%