Question

• she pays $0.75 for each paperback book. • charlene pays a customer a total of $199.75 for 149 used books. which system of equations could be used to determine the number of hardback books (x) and the number of paperback books (y) charlene purchases from the customer? 1. $x + y = 199.75$ $0.75x + 3.50y = 149$ 2. $x + y = 149$ $0.75x + 3.50y = 199.75$ 3. $x + y = 199.75$ $3.50x + 0.75y = 149$

Explanation:

Step1: Define total book count

Let $x$ = number of hardback books, $y$ = number of paperback books. Total books: $x + y = 149$

Step2: Define total cost

Cost per hardback: $\$3.50$, cost per paperback: $\$0.75$. Total cost: $3.50x + 0.75y = 199.75$

Step3: Match to options

Compare the two equations to the given choices. Option 2 has the correct total book count equation, with a transposed but equivalent cost equation (addition is commutative: $0.75x + 3.50y = 3.50x + 0.75y$)

Answer:

1. $x + y = 149$

$0.75x + 3.50y = 199.75$