Question

for a standard normal distribution, find the approximate value of p(z ≤ 0.42). use the portion of the standard normal table below to help answer the question.

z	probability
0.22	0.5871
0.32	0.6255
0.42	0.6628
0.44	0.6700
0.64	0.7389
0.84	0.7995
1.00	0.8413

16%
34%
66%
84%

Explanation:

Step1: Locate z - value in table

Find 0.42 in the z - column of the standard normal table.

Step2: Read corresponding probability

The probability value corresponding to z = 0.42 is 0.6628.

Step3: Convert to percentage

0.6628×100% = 66.28% ≈ 66%

Answer:

66%