Question

for the standard normal distribution shown on the right, find the probability of z occurring in the indicated region. click here to view page 1 of the standard normal table. click here to view page 2 of the standard normal table. the probability is . (round to four decimal places as needed.)

Explanation:

Step1: Use standard - normal table

The standard - normal table gives the cumulative probability $P(Z\leq z)$. We want to find $P(Z > - 0.82)$.
Since the total area under the standard - normal curve is 1, and $P(Z\leq z)+P(Z > z)=1$.

Step2: Look up value in table

Looking up $z=-0.82$ in the standard - normal table, we find that $P(Z\leq - 0.82)=0.2061$.

Step3: Calculate the required probability

$P(Z > - 0.82)=1 - P(Z\leq - 0.82)=1 - 0.2061 = 0.7939$.

Answer:

$0.7939$