Question

stans steakhouse is trying to determine the average amount of time customers wait before being seated at their table. each of the waiters for the restaurant randomly surveyed 10 of their customers over the course of the week. here are the data from one waiter: 10, 2, 5, 5, 0, 15, 5, 15, 10, 8. what is the mean wait time for this waiter’s data? minutes

Explanation:

Step1: Sum all the data values

We add up all the wait times: \(10 + 2 + 5 + 5 + 0 + 15 + 5 + 15 + 10 + 8\)
First, calculate step by step: \(10+2 = 12\), \(12 + 5 = 17\), \(17+5 = 22\), \(22 + 0 = 22\), \(22+15 = 37\), \(37+5 = 42\), \(42+15 = 57\), \(57+10 = 67\), \(67+8 = 75\)
So the sum of the data is \(75\).

Step2: Divide the sum by the number of data points

There are \(10\) data points (since each waiter surveyed \(10\) customers). The formula for the mean \(\bar{x}=\frac{\sum_{i = 1}^{n}x_{i}}{n}\), where \(n = 10\) and \(\sum_{i=1}^{n}x_{i}=75\).
So the mean is \(\frac{75}{10}=7.5\)

Answer:

\(7.5\)