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are starting with a cell that has the number of chromosomes, chromatids…

Question

are starting with a cell that has the number of chromosomes, chromatids, dna, and cell number as shown in line of the table. (g1 of interphase)
for each subsequent phase, fill in the appropriate number of chromosomes, chromatids, dna, and cells.
stage of cell cycle
g1 of interphase
s of interphase
metaphase of mitosis
daughter cell at the end of mitosis and cytokinesis
daughter cell at the end of meiosis i and cytokinesis
daughter cell at the end of meiosis ii and cytokinesis
number of chromosomes
6
a
e
i
m
q
number of chromatids
0
b
f
j
n
r
mass of dna (in picograms)
40
c
g
k
o
s
number of cells
1
d
h
l
p
t

Explanation:

Step1: G2 of interphase

DNA replication occurs in S - phase which is between G1 and G2. After DNA replication, the number of chromosomes remains the same (6), each chromosome consists of two sister - chromatids, so the number of chromatids is 12, the mass of DNA doubles to 80 picograms, and the number of cells is still 1. So A = 6, B = 12, C = 80, D = 1.

Step2: Metaphase of Mitosis

In metaphase of mitosis, the chromosomes line up at the equator. The number of chromosomes is 6, the number of chromatids is 12 (as each chromosome has 2 chromatids), the mass of DNA is 80 picograms, and the number of cells is 1. So E = 6, F = 12, G = 80, H = 1.

Step3: Daughter cell at the end of Mitosis and cytokinesis

After mitosis and cytokinesis, each daughter cell has the same number of chromosomes as the parent cell (6), no chromatids (as sister - chromatids separate during anaphase and telophase), half the mass of DNA compared to the parent cell at metaphase (40 picograms), and the number of cells is 2. So I = 6, J = 0, K = 40, L = 2.

Step4: Daughter cell at the end of Meiosis I and cytokinesis

Meiosis I is a reduction - division. The number of chromosomes is reduced by half (3), each chromosome still has 2 chromatids (6 chromatids), the mass of DNA is 40 picograms, and the number of cells is 2. So M = 3, N = 6, O = 40, P = 2.

Step5: Daughter cell at the end of Meiosis II and cytokinesis

After meiosis II, the sister - chromatids separate. The number of chromosomes is 3, there are no chromatids, the mass of DNA is 20 picograms, and the number of cells is 4. So Q = 3, R = 0, S = 20, T = 4.

Answer:

A. 6
B. 12
C. 80
D. 1
E. 6
F. 12
G. 80
H. 1
I. 6
J. 0
K. 40
L. 2
M. 3
N. 6
O. 40
P. 2
Q. 3
R. 0
S. 20
T. 4