Question

a store is giving every customer who enters the store a scratch - off card labeled with numbers from 1 to 10. it is equally likely that any of the numbers from 1 to 10 will be labeled on a given card. if the card is an even number, the customer gets a 15% discount on a purchase. if the card is an odd number greater than 4, the customer gets a 25% discount. otherwise, the discount is 30%. complete parts a and b.
a. what is the probability for each discount?
15% discount:
25% discount:
30% discount:
(type integers or fractions.)

Explanation:

Step1: Identify total outcomes

Total numbers: $n=10$

Step2: Count 15% discount cases

Even numbers (2,4,6,8,10): $5$ values
Probability: $\frac{5}{10}=\frac{1}{2}$

Step3: Count 25% discount cases

Odd >4 (5,7,9): $3$ values
Probability: $\frac{3}{10}$

Step4: Count 30% discount cases

Remaining (1,3): $2$ values
Probability: $\frac{2}{10}=\frac{1}{5}$

Answer:

15% discount: $\frac{1}{2}$
25% discount: $\frac{3}{10}$
30% discount: $\frac{1}{5}$