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a students course grade is based on one midterm that counts as 10% of h…

Question

a students course grade is based on one midterm that counts as 10% of his final grade, one class project that counts as 10% of his final grade, a set of homework assignments that counts as 15% of his final grade, and a final exam that counts as 35% of his final grade. assume that a mean of 90 or above is an a, a mean of at least 80 but less than 90 is a b, and so on. his midterm score is 70, his project score is 89, his homework score is 80, and his final exam score is 65. what is his overall final score? (type an integer or a decimal. do not round.) his letter grade is (a, b, c, d, or f)?

Explanation:

Step1: Identify weights and scores

The mid - term score of 70 has a weight of 10% (or 0.1), the project score of 89 has a weight of 10% (or 0.1), the homework score of 80 has a weight of 10% (or 0.1), and the final exam score of 65 has a weight of 35% (or 0.35). The remaining weight for other components is \(1-(0.1 + 0.1+0.1 + 0.35)=0.35\). Assume the score for other components is 0 for the minimum overall score calculation.

Step2: Calculate overall final score

Use the weighted - average formula \(S = w_1x_1+w_2x_2+w_3x_3+w_4x_4+w_5x_5\), where \(w_i\) are the weights and \(x_i\) are the scores.
\[

$$\begin{align*} S&=0.1\times70 + 0.1\times89+0.1\times80+0.35\times65+0.35\times0\\ &=7 + 8.9+8+22.75+0\\ &=46.65 \end{align*}$$

\]
Since \(46.65<60\), the letter grade is F.

Answer:

His overall final score is 46.65. His letter grade is F.