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the students in marlys math class recorded the dimensions of their bedr…

Question

the students in marlys math class recorded the dimensions of their bedrooms in a frequency table. bedroom areas area (sq. ft) number of bedrooms 60≤a<80 4 80≤a<100 6 100≤a<120 5 120≤a<140 3 140≤a<160 1 create a histogram to represent the data. which statement is most likely true about the mean and the median of the data? the histogram is right - skewed, so the mean is less than the median. the histogram is right - skewed, so the mean is greater than the median. the histogram is left - skewed, so the mean is less than the median. the histogram is left - skewed, so the mean is greater than the median.

Explanation:

Step1: Analyze frequency distribution

As the frequency decreases as the area increases (4, 6, 5, 3, 1 for increasing - area intervals), the histogram will be right - skewed.

Step2: Recall property of skewed data

In a right - skewed distribution, the tail on the right side (higher values) pulls the mean towards it. So, the mean is greater than the median.

Answer:

The histogram is right - skewed, so the mean is greater than the median.