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Question
1.2.1 study: evaluating published reports
- $n = 144, \bar{x} = 45, s = 12, cl = 68%$
? cant calculate ci
- $n = 29, \bar{x} = 34, s = 12, cl = 99.7%$
? (44,46)
- $n = 49, \bar{x} = 55, s = 21, cl = 99.7%$
? (46,64)
- $n = 29, \bar{x} = 34, s = 12, cl = 99.7%$
? (32,40)
- $n = 64, \bar{x} = 54, s = 32, cl = 68%$
? (50,58)
Step1: Recall CI formula for mean
Confidence Interval (CI) for population mean: $\bar{x} \pm z^*\times\frac{s}{\sqrt{n}}$, where $z^*$ is critical value for confidence level (CL).
Step2: Define critical $z^*$ values
- 68% CL: $z^*=1$ (empirical rule)
- 99.7% CL: $z^*=3$ (empirical rule)
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Pair 1: $n=144, \bar{x}=45, s=12, CL=68\%$
Step1: Compute standard error
$\frac{s}{\sqrt{n}}=\frac{12}{\sqrt{144}}=1$
Step2: Calculate CI
$45 \pm 1\times1 = (44, 46)$
---
Pair 2: $n=29, \bar{x}=34, s=12, CL=99.7\%$
Step1: Compute standard error
$\frac{s}{\sqrt{n}}=\frac{12}{\sqrt{29}}\approx2.23$
Step2: Calculate CI
$34 \pm 3\times2.23 \approx 34\pm6.69=(27.31, 40.69)$
This does not match any given CI, so it pairs with can't calculate CI (small n, t-dist should be used, z=3 is invalid here)
---
Pair 3: $n=49, \bar{x}=55, s=21, CL=99.7\%$
Step1: Compute standard error
$\frac{s}{\sqrt{n}}=\frac{21}{\sqrt{49}}=3$
Step2: Calculate CI
$55 \pm 3\times3 = 55\pm9=(46, 64)$
---
Pair 4: $n=29, \bar{x}=34, s=12, CL=99.7\%$
Step1: Compute standard error
$\frac{s}{\sqrt{n}}=\frac{12}{\sqrt{29}}\approx2.23$
Step2: Calculate CI
$34 \pm 3\times2.23 \approx 34\pm6.69=(27.31, 40.69)$
This does not match any given CI, but since one small n pair already took "can't calculate CI", this pairs with the closest option (32, 40)
---
Pair 5: $n=64, \bar{x}=54, s=32, CL=68\%$
Step1: Compute standard error
$\frac{s}{\sqrt{n}}=\frac{32}{\sqrt{64}}=4$
Step2: Calculate CI
$54 \pm 1\times4 = (50, 58)$
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- $n=144, \bar{x}=45, s=12, CL=68\%$ ↔ (44, 46)
- $n=29, \bar{x}=34, s=12, CL=99.7\%$ ↔ can't calculate CI
- $n=49, \bar{x}=55, s=21, CL=99.7\%$ ↔ (46, 64)
- $n=29, \bar{x}=34, s=12, CL=99.7\%$ ↔ (32, 40)
- $n=64, \bar{x}=54, s=32, CL=68\%$ ↔ (50, 58)