Question

suppose (z) follows the standard normal distribution. use the calculator provided, or this table, to determine the value of (c) so that the following is true. (p(zleq c)=0.1292) carry your intermediate computations to at least four decimal places. round your answer to two decimal places.

Explanation:

Step1: Use standard - normal table

Look up the value 0.1292 in the body of the standard - normal table (z - table). The standard - normal table gives the cumulative distribution function values for the standard normal random variable \(Z\) with mean \(\mu = 0\) and standard deviation \(\sigma=1\), i.e., \(P(Z\leq z)\).

Step2: Find the z - value

Searching for the closest value to 0.1292 in the z - table, we find that the corresponding z - value \(c\) is approximately \(- 1.07\).

Answer:

\(-1.07\)