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suppose a special 41 - sided die is rolled once where each face is mark…

Question

suppose a special 41 - sided die is rolled once where each face is marked with a number 1 through 41. what is the probability that the die lands on a 21 or a 20?

Explanation:

Step1: Identify total outcomes

The die has 41 sides, so total outcomes $n = 41$.

Step2: Identify favorable outcomes

The favorable outcomes are landing on 20 or 21, so $m=2$.

Step3: Calculate probability

The probability formula is $P=\frac{m}{n}$. Substituting values, we get $P = \frac{2}{41}$.

Answer:

$\frac{2}{41}$