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Question
suppose you have a rectangle where the length is longer than the width by 5cm. the area of the rectangle is 20cm². which of the following equations can be used to solve for the width?
Step1: Let the width be $x$ cm.
Since the length is longer than the width by 5 cm, the length is $(x + 5)$ cm.
Step2: Use the area - formula of a rectangle.
The area formula of a rectangle is $A=\text{length}\times\text{width}$. Given that $A = 20$ cm², we substitute the length and width into the formula: $20=(x + 5)\times x=x(x + 5)$.
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The equation $x(x + 5)=20$ can be used to solve for the width.