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suppose you have a rectangle where the length is longer than the width …

Question

suppose you have a rectangle where the length is longer than the width by 5cm. the area of the rectangle is 20cm². which of the following equations can be used to solve for the width?

Explanation:

Step1: Let the width be $x$ cm.

Since the length is longer than the width by 5 cm, the length is $(x + 5)$ cm.

Step2: Use the area - formula of a rectangle.

The area formula of a rectangle is $A=\text{length}\times\text{width}$. Given that $A = 20$ cm², we substitute the length and width into the formula: $20=(x + 5)\times x=x(x + 5)$.

Answer:

The equation $x(x + 5)=20$ can be used to solve for the width.