Question

the table shows data for the number of customers that shopped each hour at store a and at store b on a saturday. move the options to the blanks to answer each question. which stores data has the greater mean? which stores data has the greater median? which stores data has greater range?

Explanation:

Step1: Calculate mean for store A

The formula for the mean $\bar{x}=\frac{\sum_{i = 1}^{n}x_{i}}{n}$. For store A, $n = 10$, and $\sum_{i=1}^{10}x_{i}=2 + 3+5 + 7+10+6+8+9+4+2=56$. So the mean of store A, $\bar{x}_A=\frac{56}{10}=5.6$.

Step2: Calculate mean for store B

For store B, $n = 10$, and $\sum_{i = 1}^{10}x_{i}=1+4 + 4+6+10+8+8+6+4+2=53$. So the mean of store B, $\bar{x}_B=\frac{53}{10}=5.3$. Since $5.6>5.3$, store A has a greater mean.

Step3: Calculate median for store A

First, order the data for store A: $2,2,3,4,5,6,7,8,9,10$. Since $n = 10$ (even), the median $M_A=\frac{5 + 6}{2}=5.5$.

Step4: Calculate median for store B

Order the data for store B: $1,2,4,4,4,6,6,8,8,10$. Since $n = 10$ (even), the median $M_B=\frac{4+6}{2}=5$. Since $5.5>5$, store A has a greater median.

Step5: Calculate range for store A

The range $R=\text{max}-\text{min}$. For store A, $\text{max}=10$, $\text{min}=2$, so $R_A=10 - 2=8$.

Step6: Calculate range for store B

For store B, $\text{max}=10$, $\text{min}=1$, so $R_B=10 - 1=9$. Since $9>8$, store B has a greater range.

Answer:

Which store's data has the greater mean? Store A
Which store's data has the greater median? Store A
Which store's data has greater range? Store B