Question

the table shows the height, in meters, of an object that is dropped as time passes until the object hits the ground. falling object time (sec), x: 0, 0.5, 1.0, 1.5, 2.0, 2.5, 3.0, 3.5, 4.0, 4.6; height (m), h: 100, 98.8, 95.1, 89.0, 80.4, 69.4, 55.9, 40.0, 21.6, 0. a line of best fit for the data is represented by h = -21.962x + 114.655. which statement compares the line of best fit with the actual data given by the table? according to the line of best fit, the object would have hit the ground 0.6 seconds later than the actual time the object hit the ground. according to the line of best fit, the object was dropped from a lower height. the line of best fit predicts a height of 4 meters greater than the actual height for any time given in the table. the line of best fit correctly predicts that the

Explanation:

Step1: Find actual time object hits ground

From the table, when $h = 0$, $x = 4.6$ seconds.

Step2: Find time object hits ground according to line - of - best - fit

Set $h=0$ in $h=-21.962x + 114.655$. Then $0=-21.962x + 114.655$. Solving for $x$ gives $x=\frac{114.655}{21.962}\approx5.22$ seconds.

Step3: Calculate the time difference

The difference in time is $5.22 - 4.6=0.62\approx0.6$ seconds. The line - of - best - fit gives a time when the object hits the ground that is approximately 0.6 seconds later than the actual time.

Answer:

According to the line of best fit, the object would have hit the ground 0.6 seconds later than the actual time the object hit the ground.