QUESTION IMAGE
Question
the table summarizes the distribution of age and assigned group for 90 participants in a study.
| 0 - 9 years | 10 - 19 years | 20+years | total | |
|---|---|---|---|---|
| group b | 4 | 5 | 21 | 30 |
| group c | 11 | 14 | 5 | 30 |
| total | 30 | 30 | 30 | 90 |
one of these participants will be selected at random. what is the probability of selecting a participant from group a, given that the participant is at least 10 years of age?
a $\frac{1}{6}$
b $\frac{1}{4}$
c $\frac{11}{30}$
d $\frac{1}{2}$
Step1: Find number of participants at least 10 years old
Add the totals of 10 - 19 years and 20+ years columns: $30 + 30=60$.
Step2: Find number of participants from Group A who are at least 10 years old
Add the number of participants in Group A for 10 - 19 years and 20+ years: $11 + 4 = 15$.
Step3: Calculate conditional probability
Use the formula for conditional probability $P(A|B)=\frac{P(A\cap B)}{P(B)}$. In terms of counts, it's $\frac{\text{Number in A and B}}{\text{Number in B}}$. So the probability is $\frac{15}{60}=\frac{1}{4}$.
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B. $\frac{1}{4}$