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Question
tank a: y = 900 - 11x; tank b: (table with minutes, x and water in tank (gal), y: x=0,y=985; x=1,y=975; x=2,y=965; x=3,y=955); y = mx + b (rate of change, initial value); y = -11x + 900; an error has occurred. please enter a number.
Assuming the question is about the initial amount of water in Tank A (the y - intercept of the equation \(y = - 11x+900\) or \(y = 900 - 11x\)):
Step 1: Recall the slope - intercept form
The slope - intercept form of a linear equation is \(y=mx + b\), where \(m\) is the slope (rate of change) and \(b\) is the y - intercept (initial value when \(x = 0\)).
For the equation of Tank A, \(y=900-11x\) (or \(y=- 11x + 900\)), when \(x = 0\) (at time \(x = 0\) minutes, which is the initial time), we substitute \(x = 0\) into the equation.
Step 2: Calculate the initial value
Substitute \(x = 0\) into \(y=-11x + 900\). Then \(y=-11(0)+900=900\).
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