Question

there are three tables. the first table (partially visible) has a column labeled -0.8x. the second table has x values 0, 1, 2, 3, 4 and the function $y = \frac{(4x - 2)}{2}$. the third table has x values -3, -1, 1, 3, 5 and the function $y = \frac{-3}{8}x$. we need to fill in the y - values for the given x - values in the second and third tables (and possibly the first, but its partially visible).

Explanation:

Step1: Calculate $y=\frac{-3}{8}x$ for each x

For $x=-3$: $y=\frac{-3}{8}\times(-3)=\frac{9}{8}=1.125$
For $x=-1$: $y=\frac{-3}{8}\times(-1)=\frac{3}{8}=0.375$
For $x=1$: $y=\frac{-3}{8}\times1=-\frac{3}{8}=-0.375$
For $x=3$: $y=\frac{-3}{8}\times3=-\frac{9}{8}=-1.125$
For $x=5$: $y=\frac{-3}{8}\times5=-\frac{15}{8}=-1.875$

Step2: Calculate $y=\frac{(4x-2)}{2}$ for each x

Simplify first: $y=2x-1$
For $x=0$: $y=2\times0-1=-1$
For $x=1$: $y=2\times1-1=1$
For $x=2$: $y=2\times2-1=3$
For $x=3$: $y=2\times3-1=5$
For $x=4$: $y=2\times4-1=7$

Step3: Calculate $y=-0.8x$ for each x

(Assume x values match the middle table: 0,1,2,3,4)
For $x=0$: $y=-0.8\times0=0$
For $x=1$: $y=-0.8\times1=-0.8$
For $x=2$: $y=-0.8\times2=-1.6$
For $x=3$: $y=-0.8\times3=-2.4$
For $x=4$: $y=-0.8\times4=-3.2$

Answer:

First table ($y=\frac{-3}{8}x$):

x	y
-1	$0.375$
1	$-0.375$
3	$-1.125$
5	$-1.875$

Second table ($y=\frac{4x-2}{2}$):

x	y
1	1
2	3
3	5
4	7

Third table ($y=-0.8x$):

x	y
1	-0.8
2	-1.6
3	-2.4
4	-3.2