Question

there are two boxes containing only green and white pens. box a has 10 white pens and 6 green pens. box b has 11 white pens and 9 green pens. a pen is randomly chosen from each box. list these events from least likely to most likely. event 1: choosing a white or green pen from box a. event 2: choosing a white pen from box b. event 3: choosing a white pen from box a. event 4: choosing a red pen from box b. least likely → most likely event , event , event , event

Explanation:

Step1: Calculate probabilities for each event

• Event 1: In Box A, there are only green and white pens. So the probability of choosing a white or green pen from Box A is $P_1 = 1$ since it's a certain event.
• Event 2: In Box B, there are $11 + 9=20$ pens in total. The probability of choosing a white pen from Box B is $P_2=\frac{11}{20}= 0.55$.
• Event 3: In Box A, there are $10 + 6 = 16$ pens in total. The probability of choosing a white pen from Box A is $P_3=\frac{10}{16}=\frac{5}{8}=0.625$.
• Event 4: In Box B, there are no red pens. So the probability of choosing a red pen from Box B is $P_4 = 0$ since it's an impossible event.

Step2: Compare probabilities

We have $P_4=0

Answer:

Event 4, Event 2, Event 3, Event 1