Question

1. a tractor tire has a radius of 3.5 feet. how far can the tractor travel in 50 revolutions?

Explanation:

Step1: Calculate tire circumference

The distance per revolution is the circumference of the tire, given by $C = 2\pi r$. Substitute $r = 3.5$ feet:
$C = 2\pi(3.5) = 7\pi$ feet

Step2: Total distance for 50 revolutions

Multiply circumference by number of revolutions:
$\text{Total Distance} = 50 \times 7\pi = 350\pi$
To get a numerical value, use $\pi \approx 3.1416$:
$350 \times 3.1416 = 1099.56$ feet

Answer:

$350\pi$ feet (or approximately 1100 feet, or 1099.56 feet)