Question

two dice are tossed, 1 being red and the other blue. find the probability of a 1 on the red die or a 1 on the blue die or a 1 on both dice. select an answer 1/3 1/2 1/36 11/36

Explanation:

Step1: Calculate total outcomes

When two dice are tossed, the total number of outcomes is $6\times6 = 36$ since each die has 6 faces.

Step2: Calculate number of favorable outcomes

The number of ways to get a 1 on the red die (6 cases: (1,1), (1,2), (1,3), (1,4), (1,5), (1,6)), the number of ways to get a 1 on the blue die (6 cases: (1,1), (2,1), (3,1), (4,1), (5,1), (6,1)). But we double - counted the case (1,1) once. So the number of favorable outcomes is $6 + 6-1=11$.

Step3: Calculate probability

The probability $P$ is the number of favorable outcomes divided by the total number of outcomes. So $P=\frac{11}{36}$.

Answer:

$\frac{11}{36}$