Question

two pools are being filled with water. to start, the first pool had 1950 liters of water and the second pool had 1430 liters of water. water is being added to the first pool at a rate of 33 liters per minute. water is being added to the second pool at a rate of 43 liters per minute. let x be the number of minutes water has been added. (a) for each pool, write an expression for the amount of water in the pool after x minutes. amount of water in the first pool (in liters) = 1950 amount of water in the second pool (in liters) = 1430 (b) write an equation to show when the two pools would have the same amount of water.

Explanation:

Step1: Define first pool's water amount

The initial volume is 1950 liters, plus 33 liters per minute for $x$ minutes.
$1950 + 33x$

Step2: Define second pool's water amount

The initial volume is 1430 liters, plus 43 liters per minute for $x$ minutes.
$1430 + 43x$

Step3: Set amounts equal for part (b)

Equate the two expressions to find when volumes are equal.
$1950 + 33x = 1430 + 43x$

Answer:

(a)
Amount of water in the first pool (in liters) = $1950 + 33x$
Amount of water in the second pool (in liters) = $1430 + 43x$

(b)
$1950 + 33x = 1430 + 43x$