Question

the two - way table shows the classification of students in a mathematics class by gender and dominant hand. an ambidextrous student uses both hands equally well. part a: what is the probability that a randomly selected student in the class is female given that the student is right - handed? the two - way table has rows: male, female, total; columns: right - handed, left - handed, ambidextrous, total. male row: right - handed 11, left - handed 4, ambidextrous 1, total 16. female row: right - handed 12, left - handed 2, ambidextrous 0, total 14. total row: right - handed 23, left - handed 6, ambidextrous 1, total 30. the options are 12/23, 12/30, 23/30, 1/12.

Explanation:

Step1: Identify conditional probability

We need $P(\text{Female}|\text{Right-Handed})$, calculated as $\frac{\text{Number of right-handed females}}{\text{Total number of right-handed students}}$.

Step2: Extract values from the table

Right-handed females = 12; Total right-handed = 23.

Step3: Compute the probability

Substitute values: $\frac{12}{23}$

Answer:

12/23