Question

use the accompanying radiation levels (in $\frac{w}{kg}$) for 50 different cell phones. find the percentile corresponding to 1.48 $\frac{w}{kg}$.
click the icon to view the radiation levels.
the percentile corresponding to 1.48 $\frac{w}{kg}$ is
(round to the nearest whole number as needed.)

Explanation:

Step1: Sort the data

Sort the 50 radiation - level values in ascending order.

Step2: Use the percentile formula

The formula for the percentile \(P\) of a value \(x\) in a data - set of size \(n\) is \(L=\frac{k}{100}\times n\), where \(k\) is the percentile we want to find and \(n\) is the number of data points. To find the percentile of a value \(x\), we first count the number of values less than or equal to \(x\). Let \(c\) be the number of values less than or equal to \(1.48\frac{W}{kg}\). Then the percentile \(P=\frac{c}{n}\times100\), where \(n = 50\).
Since we don't have the actual data set, assume we have counted \(c\) values less than or equal to \(1.48\frac{W}{kg}\).

Step3: Calculate the percentile

If we assume we find that \(c\) values are less than or equal to \(1.48\frac{W}{kg}\), then \(P=\frac{c}{50}\times100 = 2c\).
Let's assume after sorting the data and counting, we find that \(c = 30\) (this is just an example as the actual data is not given). Then \(P=\frac{30}{50}\times100=60\).

Answer:

(The actual answer depends on the actual data set. But if we assume the above - mentioned example situation) 60