QUESTION IMAGE
Question
use the frequency distribution shown below to construct an expanded frequency distribution. high temperatures (°f)
class 20 - 30 31 - 41 42 - 52 53 - 63 64 - 74 75 - 85 86 - 96
frequency, f 17 44 68 69 76 68 23
complete the table below. high temperatures (°f) (round to the nearest hundredth as needed.)
class frequency, f midpoint relative frequency cumulative frequency
20 - 30 17
Step1: Calculate mid - point
The mid - point of a class interval $a - b$ is $\frac{a + b}{2}$. For the class $20 - 30$, the mid - point is $\frac{20+30}{2}=25$.
Step2: Calculate total frequency
The total frequency $n=17 + 44+68+69+76+68+23=365$.
Step3: Calculate relative frequency
The relative frequency of a class is $\frac{f}{n}$. For the class $20 - 30$ with $f = 17$, the relative frequency is $\frac{17}{365}\approx0.05$.
Step4: Calculate cumulative frequency
The cumulative frequency of the first class is equal to its frequency. For the class $20 - 30$, the cumulative frequency is $17$.
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| Class | Frequency, f | Midpoint | Relative frequency | Cumulative frequency |
|---|