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use the standard normal table to find the z - score that corresponds to…

Question

use the standard normal table to find the z - score that corresponds to the given percentile. if the area is not in the table, use the entry closest to the area. if the area is halfway between two entries, use the z - score halfway between the corresponding z - scores. if convenient, use technology to find the z - score. p82 click to view page 1 of the table. click to view page 2 of the table. the z - score that corresponds to p82 is . (round to two decimal places as needed.)

Explanation:

Step1: Understand the percentile meaning

$P_{82}$ means the area to the left of the z - score is 0.82.

Step2: Look up in standard normal table

Search for the value closest to 0.82 in the body of the standard - normal table. The closest value in the standard normal table to 0.82 is 0.8190 which corresponds to a z - score of 0.91 and 0.8212 which corresponds to a z - score of 0.92.

Step3: Interpolate (if necessary)

Since 0.82 is closer to 0.8212, the z - score corresponding to $P_{82}$ is approximately 0.92.

Answer:

0.92