Question

what amino acid sequence would result from the following mrna? gene a mrna sequence: 5 ccc aug ucc uac uuc cca cag gcc uaa uuu 3 pro met ser tyr phe pro gln ala pro met ser tyr phe pro gln ala phe met ser tyr phe pro gln ala phe met ser tyr phe pro gln ala question 4 which is not a difference between transcription in prokaryotic and eukaryotic cells? in prokaryotes transcription and translation happen at the same time and place only eukaryotes use uracil in their rna eukaryotes transcribe their genes in the nucleus eukaryotes can splice their genes

Explanation:

Step1: Identify start and stop codons

The start codon is AUG which codes for Methionine (Met). UAA is a stop codon which terminates translation.

Step2: Translate codons

CCC codes for Proline (Pro), AUG for Methionine (Met), UCC for Serine (Ser), UAC for Tyrosine (Tyr), UUC for Phenylalanine (Phe), CCA for Proline (Pro), CAG for Glutamine (Gln), GCC for Alanine (Ala), UAA is a stop codon and UUU after stop is not translated.

Step1: Analyze transcription differences

In prokaryotes, transcription and translation are coupled (happen at same time and place). Eukaryotes transcribe in nucleus and can splice genes. Both prokaryotes and eukaryotes use uracil in RNA.

Answer:

Met Ser Tyr Phe Pro Gln Ala