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when two balanced dice are rolled, 36 equally likely outcomes are possi…

Question

when two balanced dice are rolled, 36 equally likely outcomes are possible, as depicted in the accompanying figure. let y denote the sum of the dice. complete parts (a) through (g) below. a. what are the possible values of the random variable y? y = 2,3,4,5,6,7,8,9,10,11,12 (type whole numbers. use a comma to separate answers as needed.) b. use random - variable notation to represent the event that the sum of the dice is 3. select the correct choice below and fill in the answer box within your choice. a. {y = 3} b. p( ) c. find the probability that the sum of the dice is 3. the probability is (type an integer or a simplified fraction.)

Explanation:

Step1: Identify favorable outcomes

The pairs of dice - values that sum to 3 are (1, 2) and (2, 1). So there are 2 favorable outcomes.

Step2: Calculate probability

The total number of outcomes when two dice are rolled is 36. The probability $P$ of an event is given by the formula $P=\frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}}$. So $P=\frac{2}{36}=\frac{1}{18}$.

Answer:

$\frac{1}{18}$