Question

which event has a theoretical probability of exactly $\frac{3}{4}$? select three options.
not picking a square
picking a square
picking a triangle
picking a shape that has only straight edges
not picking a circle

Explanation:

Step1: Count total shapes

There are 8 shapes in total.

Step2: Analyze "not picking a square"

There are 2 squares. So number of non - square shapes is 8 - 2=6. Probability of not picking a square is $\frac{6}{8}=\frac{3}{4}$.

Step3: Analyze "picking a square"

Probability of picking a square is $\frac{2}{8}=\frac{1}{4}$.

Step4: Analyze "picking a triangle"

There are 4 triangles. Probability of picking a triangle is $\frac{4}{8}=\frac{1}{2}$.

Step5: Analyze "picking a shape that has only straight edges"

Squares and triangles have straight edges. There are 2 squares and 4 triangles, so 2 + 4 = 6 such shapes. Probability is $\frac{6}{8}=\frac{3}{4}$.

Step6: Analyze "not picking a circle"

There are 2 circles. So number of non - circle shapes is 8 - 2 = 6. Probability of not picking a circle is $\frac{6}{8}=\frac{3}{4}$.

Answer:

not picking a square, picking a shape that has only straight edges, not picking a circle