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which situation can be represented by the inequality 15 + 6x ≤ 100? laz…

Question

which situation can be represented by the inequality 15 + 6x ≤ 100? lazer zone charges $6 plus $15 per person. if andrea has a maximum of $100 to spend, how many people can andrea invite to play laser tag? lazer zone charges $6 plus $15 per person. if andrea has a minimum of $100 to spend, how many people can andrea invite to play laser tag? lazer zone charges $15 plus $6 per person. if andrea has a maximum of $100 to spend, how many people can andrea invite to play laser tag? lazer zone charges $15 plus $6 per person. if andrea has a minimum of $100 to spend, how many people can andrea invite to play laser tag?

Explanation:

Step1: Analyze the inequality structure

The inequality is \(15 + 6x\leq100\). Here, \(15\) is a fixed cost, \(6\) is the cost per person (so \(6x\) is the cost for \(x\) people), and \(\leq100\) means the total cost is at most (maximum) \(100\).

Step2: Analyze each option

  • Green option: Says \(\$6\) plus \(\$15\) per person. But our inequality has \(15 + 6x\), so this is reversed. Eliminate.
  • Purple option: Talks about minimum of \(\$100\) to spend, but our inequality is \(\leq100\) (maximum), so eliminate.
  • Orange option: Says \(\$15\) plus \(\$6\) per person (matches \(15 + 6x\)) and maximum of \(\$100\) to spend (matches \(\leq100\)). This fits.
  • Blue option: Talks about minimum of \(\$100\), which doesn't match \(\leq100\) (maximum). Eliminate.

Answer:

Orange option: Lazer Zone charges \$15 plus \$6 per person. If Andrea has a maximum of \$100 to spend, how many people can Andrea invite to play laser tag?