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Question
worksheet 2: center & spread (s.id.2)
part a: distribution shape
the test scores below are shown:
62, 65, 70, 72, 75, 78, 80, 85, 92
- describe the shape of the distribution (symmetric, skewed left, skewed right).
- calculate the mean and median.
- which measure of center best represents the data? explain.
part b: outliers
another class has the following scores:
60, 72, 75, 78, 80, 82, 85, 88, 100
- identify any outliers.
- should the mean or median be used? justify your answer.
Step1: Analyze distribution shape
Compare low and high score spreads: Low scores (62,65,70,72,75) have smaller gaps; high scores (78,80,85,92) have larger gaps, pulling the right tail longer.
Step2: Calculate mean of first dataset
Sum all scores, divide by count.
$\text{Mean} = \frac{62+65+70+72+75+78+80+85+92}{9} = \frac{679}{9} \approx 75.44$
Step3: Calculate median of first dataset
Find middle value of ordered data (9 values, 5th is median).
$\text{Median} = 75$
Step4: Evaluate best center measure
Distribution is skewed right; median resists skew better.
Step5: Find quartiles for second dataset
Ordered data: 60,72,75,78,80,82,85,88,100. $Q_1=75$, $Q_3=85$.
Step6: Calculate IQR and outlier bounds
$\text{IQR}=Q_3-Q_1=85-75=10$. Lower bound: $Q_1-1.5\times\text{IQR}=75-15=60$. Upper bound: $Q_3+1.5\times\text{IQR}=85+15=100$.
Step7: Evaluate center measure for outliers
Dataset has no outliers, but check skew; mean is suitable if symmetric.
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- Skewed right
- Mean: $\approx 75.44$, Median: $75$
- The median best represents the data. The distribution is skewed right, and the median is not affected by the larger spread of high scores (skew) as much as the mean.
- There are no outliers. All scores fall within the bounds $60 \leq x \leq 100$.
- The mean can be used. There are no outliers, and the distribution is roughly symmetric, so the mean accurately reflects the center of the data.