QUESTION IMAGE
Question
write the answer for each problem. if you dont know how to work the problem, put an x over it and move to the next problem. complete the problems in order. simplify fractions to their most common form.
48 + 16 + 3
1\frac{2}{3} \times 4\frac{1}{3}
\frac{2}{5} \div \frac{1}{5}
\frac{-936}{18}
1\frac{1}{4} \times 3\frac{2}{3}
\frac{1}{3} \div 70
-63 \times -38
11.2 \overline{)175.84}
\frac{20}{25} \div \frac{1}{10}
9 - 22
108 \times -141
3.4 \times 5.2
-23 - 2 - (-8)
\frac{3}{10} \times \frac{4}{5}
-224 \div -14
\copyright 2025 the university of texas system/texas education agency. licensed under cc - by - nd - nc 4.0 international.
Step1: Solve 48 + 16 + 3
$48 + 16 + 3 = 67$
Step2: Solve $1\frac{2}{3} \times 4\frac{1}{3}$
Convert to improper fractions: $1\frac{2}{3}=\frac{5}{3}$, $4\frac{1}{3}=\frac{13}{3}$
$\frac{5}{3} \times \frac{13}{3} = \frac{65}{9} = 7\frac{2}{9}$
Step3: Solve $\frac{2}{5} \div \frac{1}{5}$
$\frac{2}{5} \times \frac{5}{1} = 2$
Step4: Solve $\frac{-936}{18}$
$\frac{-936}{18} = -52$
Step5: Solve $2\frac{1}{4} \times 3\frac{2}{3}$
Convert to improper fractions: $2\frac{1}{4}=\frac{9}{4}$, $3\frac{2}{3}=\frac{11}{3}$
$\frac{9}{4} \times \frac{11}{3} = \frac{99}{12} = \frac{33}{4} = 8\frac{1}{4}$
Step6: Solve $\frac{1}{3} \div 70$
$\frac{1}{3} \times \frac{1}{70} = \frac{1}{210}$
Step7: Solve $-63 \times -38$
$(-63) \times (-38) = 2394$
Step8: Solve $175.84 \div 11.2$
$175.84 \div 11.2 = 15.7$
Step9: Solve $\frac{20}{25} \div \frac{1}{10}$
Simplify $\frac{20}{25}=\frac{4}{5}$, then $\frac{4}{5} \times 10 = 8$
Step10: Solve $9 - 22$
$9 - 22 = -13$
Step11: Solve $108 \times -141$
$108 \times (-141) = -15228$
Step12: Solve $3.4 \times 5.2$
$3.4 \times 5.2 = 17.68$
Step13: Solve $-23 - 2 - (-8)$
$-23 - 2 + 8 = -17$
Step14: Solve $\frac{3}{10} \times \frac{4}{5}$
$\frac{3 \times 4}{10 \times 5} = \frac{12}{50} = \frac{6}{25}$
Step15: Solve $-224 \div -14$
$(-224) \div (-14) = 16$
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- $67$
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