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adding compounds worksheet 2 2c₂h₅oh 1. carbon = 4 2. hydrogen = 12 3. …

Question

adding compounds worksheet 2
2c₂h₅oh

  1. carbon = 4
  2. hydrogen = 12
  3. oxygen = 2

2al + 3o₂

  1. aluminum = 2
  2. oxygen = 6

h₂so₄ + 2hi

  1. hydrogen =
  2. sulfur =
  3. oxygen =
  4. iodine =

k₂o + h₂o

  1. potassium =
  2. oxygen =
  3. hydrogen =

co₂ + 2h₂o

  1. carbon =
  2. oxygen =
  3. hydrogen =

c₆h₁₂o₆ + 3o₂

  1. carbon =
  2. oxygen =
  3. hydrogen =

si₂h₃ + 2h₂o

  1. silicon =
  2. hydrogen =
  3. oxygen =

2naoh + 4h₂ + o₃

  1. sodium =
  2. hydrogen =
  3. oxygen =

3na₃po₄ + mgcl₂ + o₂

  1. sodium =
  2. phosphorus =
  3. oxygen =
  4. magnesium =
  5. chlorine =

Explanation:

Step1: Count atoms in $H_2SO_4 + 2HI$

For hydrogen, in $H_2SO_4$ there are 2 H - atoms and in 2HI there are 2 H - atoms, so total H = 4; sulfur in $H_2SO_4$ is 1; oxygen in $H_2SO_4$ is 4; iodine in 2HI is 2.

  1. Hydrogen = 4
  2. Sulfur = 1
  3. Oxygen = 4
  4. Iodine = 2

Step2: Count atoms in $K_2O + H_2O$

Potassium in $K_2O$ is 2; oxygen in $K_2O$ and $H_2O$ combined is 2; hydrogen in $H_2O$ is 2.

  1. Potassium = 2
  2. Oxygen = 2
  3. Hydrogen = 2

Step3: Count atoms in $CO_2+2H_2O$

Carbon in $CO_2$ is 1; oxygen in $CO_2$ and 2$H_2O$ combined is 4; hydrogen in 2$H_2O$ is 4.

  1. Carbon = 1
  2. Oxygen = 4
  3. Hydrogen = 4

Step4: Count atoms in $C_6H_{12}O_6 + 3O_2$

Carbon in $C_6H_{12}O_6$ is 6; oxygen in $C_6H_{12}O_6$ and 3$O_2$ combined is 12; hydrogen in $C_6H_{12}O_6$ is 12.

  1. Carbon = 6
  2. Oxygen = 12
  3. Hydrogen = 12

Step5: Count atoms in $Si_2H_3+2H_2O$

Silicon in $Si_2H_3$ is 2; hydrogen in $Si_2H_3$ and 2$H_2O$ combined is 7; oxygen in 2$H_2O$ is 2.

  1. Silicon = 2
  2. Hydrogen = 7
  3. Oxygen = 2

Step6: Count atoms in $2NaOH + 4H_2+O_3$

Sodium in 2$NaOH$ is 2; hydrogen in 2$NaOH$ and 4$H_2$ combined is 10; oxygen in 2$NaOH$ and $O_3$ combined is 5.

  1. Sodium = 2
  2. Hydrogen = 10
  3. Oxygen = 5

Step7: Count atoms in $3Na_3PO_4+MgCl_2+O_2$

Sodium in 3$Na_3PO_4$ is 9; phosphorus in 3$Na_3PO_4$ is 3; oxygen in 3$Na_3PO_4$ and $O_2$ combined is 14; magnesium in $MgCl_2$ is 1; chlorine in $MgCl_2$ is 2.

  1. Sodium = 9
  2. Phosphorus = 3
  3. Oxygen = 14
  4. Magnesium = 1
  5. Chlorine = 2

Answer:

  1. 4
  2. 1
  3. 4
  4. 2
  5. 2
  6. 2
  7. 2
  8. 1
  9. 4
  10. 4
  11. 6
  12. 12
  13. 12
  14. 2
  15. 7
  16. 2
  17. 2
  18. 10
  19. 5
  20. 9
  21. 3
  22. 14
  23. 1
  24. 2