QUESTION IMAGE
Question
adding compounds worksheet 2
2c₂h₅oh
- carbon = 4
- hydrogen = 12
- oxygen = 2
2al + 3o₂
- aluminum = 2
- oxygen = 6
h₂so₄ + 2hi
- hydrogen =
- sulfur =
- oxygen =
- iodine =
k₂o + h₂o
- potassium =
- oxygen =
- hydrogen =
co₂ + 2h₂o
- carbon =
- oxygen =
- hydrogen =
c₆h₁₂o₆ + 3o₂
- carbon =
- oxygen =
- hydrogen =
si₂h₃ + 2h₂o
- silicon =
- hydrogen =
- oxygen =
2naoh + 4h₂ + o₃
- sodium =
- hydrogen =
- oxygen =
3na₃po₄ + mgcl₂ + o₂
- sodium =
- phosphorus =
- oxygen =
- magnesium =
- chlorine =
Step1: Count atoms in $H_2SO_4 + 2HI$
For hydrogen, in $H_2SO_4$ there are 2 H - atoms and in 2HI there are 2 H - atoms, so total H = 4; sulfur in $H_2SO_4$ is 1; oxygen in $H_2SO_4$ is 4; iodine in 2HI is 2.
- Hydrogen = 4
- Sulfur = 1
- Oxygen = 4
- Iodine = 2
Step2: Count atoms in $K_2O + H_2O$
Potassium in $K_2O$ is 2; oxygen in $K_2O$ and $H_2O$ combined is 2; hydrogen in $H_2O$ is 2.
- Potassium = 2
- Oxygen = 2
- Hydrogen = 2
Step3: Count atoms in $CO_2+2H_2O$
Carbon in $CO_2$ is 1; oxygen in $CO_2$ and 2$H_2O$ combined is 4; hydrogen in 2$H_2O$ is 4.
- Carbon = 1
- Oxygen = 4
- Hydrogen = 4
Step4: Count atoms in $C_6H_{12}O_6 + 3O_2$
Carbon in $C_6H_{12}O_6$ is 6; oxygen in $C_6H_{12}O_6$ and 3$O_2$ combined is 12; hydrogen in $C_6H_{12}O_6$ is 12.
- Carbon = 6
- Oxygen = 12
- Hydrogen = 12
Step5: Count atoms in $Si_2H_3+2H_2O$
Silicon in $Si_2H_3$ is 2; hydrogen in $Si_2H_3$ and 2$H_2O$ combined is 7; oxygen in 2$H_2O$ is 2.
- Silicon = 2
- Hydrogen = 7
- Oxygen = 2
Step6: Count atoms in $2NaOH + 4H_2+O_3$
Sodium in 2$NaOH$ is 2; hydrogen in 2$NaOH$ and 4$H_2$ combined is 10; oxygen in 2$NaOH$ and $O_3$ combined is 5.
- Sodium = 2
- Hydrogen = 10
- Oxygen = 5
Step7: Count atoms in $3Na_3PO_4+MgCl_2+O_2$
Sodium in 3$Na_3PO_4$ is 9; phosphorus in 3$Na_3PO_4$ is 3; oxygen in 3$Na_3PO_4$ and $O_2$ combined is 14; magnesium in $MgCl_2$ is 1; chlorine in $MgCl_2$ is 2.
- Sodium = 9
- Phosphorus = 3
- Oxygen = 14
- Magnesium = 1
- Chlorine = 2
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