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the minimum of the data is the first quartile is the median of the data…

Question

the minimum of the data is
the first quartile is
the median of the data is
the third quartile is
the maximum of the data is
done
weight of female dogs (lb.)
4 | 0 1 3
5 | 0 8
6 | 1 2 3 5
7 | 8
8 |
9 | 7

Explanation:

Step1: List all data values

From the stem-and-leaf plot, the data is: 40, 41, 43, 50, 58, 61, 62, 63, 65, 78, 97

Step2: Find minimum value

The smallest value in the dataset is the first entry.
Minimum = 40

Step3: Find median (2nd quartile)

There are 11 data points. The median is the $\frac{11+1}{2}=6$th value.
6th value: 61

Step4: Find first quartile (Q1)

Q1 is the median of the lower half (first 5 values: 40,41,43,50,58), which is the 3rd value.
Q1 = 43

Step5: Find third quartile (Q3)

Q3 is the median of the upper half (last 5 values: 62,63,65,78,97), which is the 3rd value of this subset.
Q3 = 65

Step6: Find maximum value

The largest value in the dataset is the last entry.
Maximum = 97

Answer:

The minimum of the data is 40
The first quartile is 43
The median of the data is 61
The third quartile is 65
The maximum of the data is 97