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name class date 8-3 practice form k write an equation of the function $…

Question

name
class date
8-3 practice
form k
write an equation of the function $g(x)$ and describe the effects on the graph of the parent function $f(x)=x^2$.

  1. $g(x)=f(x)+d$, where $d=6$
  2. $g(x)=f(x-c)$, where $c=-4$
  3. $g(x)=af(x)$, where $a=-2$
  4. $g(x)=f(hx)$, where $h=0.8$

sketch the graphs of each pair of functions on the same coordinate grid. identify the vertex of each graph. if the second graph is a transformation of the first, identify the transformation as a stretch, compression, reflection, or translation.

  1. $f(x)=x^2, g(x)=(-4x)^2$
  2. $f(x)=\frac{1}{2}(x-1)^2, g(x)=\frac{1}{2}(x-1)^2+3$

Explanation:

Step1: Substitute $f(x)=x^2$ into $g(x)$

$g(x) = x^2 + 6$

Step2: Substitute $f(x)=x^2$ into $g(x)$

$g(x) = (x - (-4))^2 = (x+4)^2$

Step3: Substitute $f(x)=x^2$ into $g(x)$

$g(x) = -2x^2$

Step4: Substitute $f(x)=x^2$ into $g(x)$

$g(x) = (0.8x)^2 = 0.64x^2$

Step5: Rewrite $g(x)$ and identify transformation

$g(x) = (-4x)^2 = 16x^2$

Step6: Compare $g(x)$ to $f(x)$ for transformation

$g(x) = \frac{1}{2}(x-1)^2 + 3$

Answer:

  1. $g(x)=x^2+6$; The graph of the parent function $f(x)=x^2$ is translated 6 units upward. Vertex of $f(x)$ is $(0,0)$, vertex of $g(x)$ is $(0,6)$.
  2. $g(x)=(x+4)^2$; The graph of the parent function $f(x)=x^2$ is translated 4 units to the left. Vertex of $f(x)$ is $(0,0)$, vertex of $g(x)$ is $(-4,0)$.
  3. $g(x)=-2x^2$; The graph of the parent function $f(x)=x^2$ is reflected over the x-axis and vertically stretched by a factor of 2. Vertex of $f(x)$ is $(0,0)$, vertex of $g(x)$ is $(0,0)$.
  4. $g(x)=(0.8x)^2=0.64x^2$; The graph of the parent function $f(x)=x^2$ is horizontally compressed by a factor of $\frac{1}{0.8}=1.25$. Vertex of $f(x)$ is $(0,0)$, vertex of $g(x)$ is $(0,0)$.
  5. $g(x)=(-4x)^2=16x^2$; The graph of the parent function $f(x)=x^2$ is horizontally compressed by a factor of $\frac{1}{4}$ (the negative sign results in a reflection over the y-axis, but since $x^2$ is even, this has no visible change). Vertex of $f(x)$ is $(0,0)$, vertex of $g(x)$ is $(0,0)$.
  6. $g(x)=\frac{1}{2}(x-1)^2+3$; The graph of the parent function $f(x)=\frac{1}{2}(x-1)^2$ is translated 3 units upward. Vertex of $f(x)$ is $(1,0)$, vertex of $g(x)$ is $(1,3)$.

(Note: For the graphing portions, plot the vertex and additional points (e.g., $x=\pm1, \pm2$ for parent functions) to sketch each transformed curve on the provided grids.)