Question

2.08 - solve linear equations with fractions
due sunday by 11:59pm points 100 submitting an external tool available sep
question
solve: $-\frac{1}{5}(3c - 4)=-2(-c - 2)$.
provide your answer below:

Explanation:

Step1: Distribute on both sides

$-\frac{1}{5}(3c - 4)=-\frac{3c}{5}+\frac{4}{5}$ and $-2(-c - 2)=2c + 4$. So the equation becomes $-\frac{3c}{5}+\frac{4}{5}=2c + 4$.

Step2: Multiply through by 5 to clear the fraction

$5\times(-\frac{3c}{5}+\frac{4}{5})=5\times(2c + 4)$. This gives $-3c + 4 = 10c+20$.

Step3: Move variable terms to one - side

Add $3c$ to both sides: $-3c+3c + 4=10c+3c + 20$, which simplifies to $4 = 13c+20$.

Step4: Move constant terms to the other side

Subtract 20 from both sides: $4-20=13c+20 - 20$, resulting in $-16 = 13c$.

Step5: Solve for c

Divide both sides by 13: $c=-\frac{16}{13}$.

Answer:

$c = -\frac{16}{13}$