Question

1. calculate the water potential of the celery cells at 23°c.

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1. you determined the water potential of the potato to be -9.8 bars. you determined the water potential of the celery to be student response bars.

compare their water potential, osmolarity, and solute concentrations.

Explanation:

Step1: Find isotonic molarity

From the graph, the linear fit crosses 0% mass change at a NaCl molarity of ~0.15 mol/L. Since NaCl dissociates into 2 ions, the osmolarity is $0.15 \times 2 = 0.30$ osmol/L.

Step2: Apply water potential formula

Use the formula $\Psi = -iCRT$, where $i=2$, $C=0.15$ mol/L, $R=0.0831$ L·bar/(mol·K), $T=23+273=296$ K.
$\Psi = -(2) \times 0.15 \times 0.0831 \times 296$
$\Psi = -0.3 \times 0.0831 \times 296$
$\Psi = -0.3 \times 24.5976$

Answer:

-7.38 bars (or ~-7.4 bars)