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about 5% of the population has a particular genetic mutation. 200 peopl…

Question

about 5% of the population has a particular genetic mutation. 200 people are randomly selected. find the mean for the number of people with the genetic mutation in such groups of 200.

Explanation:

Step1: Identify the formula

The mean of a binomial distribution is given by $\mu = np$, where $n$ is the number of trials and $p$ is the probability of success on a single - trial.

Step2: Define the values of $n$ and $p$

Here, $n = 200$ (the number of people selected) and $p=0.05$ (the probability of a person having the genetic mutation).

Step3: Calculate the mean

$\mu=np = 200\times0.05=10$.

Answer:

10