Question

1. calculate the high power magnification of this microscope. show your formula and all work.
2. describe the changes in the field of view and the amount of available light when going from low to high power using the compound microscope.
3. explain what the microscope user may have to do to combat the problems incurred in question # 6.
4. how does the procedure for using the microscope differ under high power as opposed to low power?

Explanation:

7.

Step1: Recall magnification formula

The high - power magnification of a compound microscope is given by the product of the magnification of the eyepiece ($M_e$) and the high - power objective lens ($M_o$). The formula is $M = M_e\times M_o$.
Let's assume the eyepiece magnification $M_e = 10\times$ and the high - power objective magnification $M_o=40\times$.

Step2: Calculate magnification

$M=10\times40 = 400\times$

When going from low to high power on a compound microscope, the field of view decreases. This is because a higher - power objective lens has a narrower angle of view. Also, the amount of available light decreases. A high - power objective lens has a smaller aperture, which allows less light to pass through.

Since question 6 is not provided, assuming the problem is related to low light or small field of view. To combat low light, the user can adjust the diaphragm to allow more light in or use a light source with higher intensity. To deal with a small field of view, the user can first locate the specimen under low power and then switch to high power.

Answer:

$400\times$

8.